Find the range of values for the third side of a triangle if two of its sides measure 42.7 mm and 38.03 mm.(1 point)

Responses

4.04<x<80.1
4.04 less than x less than 80.1

4.67<x<80.73
4.67 less than x less than 80.73

4.67<x<42.3
4.67 less than x less than 42.3

4.4<x<80.73

1 answer

To find the range of values for the third side of a triangle when given two sides \( a \) and \( b \), we can use the triangle inequality theorem. The theorem states:

  1. \( a + b > c \)
  2. \( a + c > b \)
  3. \( b + c > a \)

Where \( c \) is the length of the third side. Let's denote the two given sides as follows:

  • \( a = 42.7 , \text{mm} \)
  • \( b = 38.03 , \text{mm} \)

Using the triangle inequalities:

  1. From \( a + b > c \): \[ 42.7 + 38.03 > c \Rightarrow 80.73 > c \Rightarrow c < 80.73 \]

  2. From \( a + c > b \): \[ 42.7 + c > 38.03 \Rightarrow c > 38.03 - 42.7 \Rightarrow c > -4.67 \] Since the length of a side cannot be negative, we have \( c > 0 \).

  3. From \( b + c > a \): \[ 38.03 + c > 42.7 \Rightarrow c > 42.7 - 38.03 \Rightarrow c > 4.67 \]

Combining these inequalities, we find: \[ 4.67 < c < 80.73 \]

Thus, the range of values for the third side \( c \) is: \[ 4.67 < c < 80.73 \]

Therefore, the correct response is: 4.67 < x < 80.73.