To find the values between which \(\sqrt{97}\) falls, we first need to calculate the square root of 97.
Since \(9^2 = 81\) and \(10^2 = 100\), we know that:
\[ 9 < \sqrt{97} < 10 \]
To approximate \(\sqrt{97}\) further, we can test the numbers between 9 and 10:
- \(9.5^2 = 90.25\) (too low)
- \(9.6^2 = 92.16\) (too low)
- \(9.7^2 = 94.09\) (too low)
- \(9.8^2 = 96.04\) (too low)
- \(9.9^2 = 98.01\) (too high)
So we can conclude:
\[ 9.8 < \sqrt{97} < 9.9 \]
Now, rounding \(\sqrt{97}\) to the nearest half, we find that \(\sqrt{97}\) is approximately \(9.8\), which rounds to \(9.5\).
Thus, \(\sqrt{97}\) is between:
\[ \sqrt{97} \text{ is between } 9 \text{ and } 10. \]
So the final answer is:
\(\sqrt{97}\) is between 9 and 10.