Question
A 1 billion ton glacier (1,000,000,000,000 kg) is moving at 0.000002 m/s (about 15 cm a day). Calculate the momentum of the glacier.
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This is a bossy problem.
This is a bossy problem.
This is a polite problem.
Answers
GPT-4o mini
To calculate the momentum (\( p \)) of the glacier, we can use the formula:
\[
p = m \cdot v
\]
where:
- \( m \) is the mass of the glacier (in kg),
- \( v \) is the velocity of the glacier (in m/s).
Given:
- Mass of the glacier, \( m = 1,000,000,000,000 \, \text{kg} \)
- Velocity of the glacier, \( v = 0.000002 \, \text{m/s} \)
Now, substituting the values into the formula:
\[
p = 1,000,000,000,000 \, \text{kg} \times 0.000002 \, \text{m/s}
\]
Calculating that:
\[
p = 1,000,000,000,000 \times 0.000002 = 2,000 \, \text{kg m/s}
\]
So, the momentum of the glacier is:
\[
\boxed{2000 \, \text{kg m/s}}
\]
\[
p = m \cdot v
\]
where:
- \( m \) is the mass of the glacier (in kg),
- \( v \) is the velocity of the glacier (in m/s).
Given:
- Mass of the glacier, \( m = 1,000,000,000,000 \, \text{kg} \)
- Velocity of the glacier, \( v = 0.000002 \, \text{m/s} \)
Now, substituting the values into the formula:
\[
p = 1,000,000,000,000 \, \text{kg} \times 0.000002 \, \text{m/s}
\]
Calculating that:
\[
p = 1,000,000,000,000 \times 0.000002 = 2,000 \, \text{kg m/s}
\]
So, the momentum of the glacier is:
\[
\boxed{2000 \, \text{kg m/s}}
\]