Question
What is the momentum of a 15 gram (0.015kg) bullet traveling at 280 m/s.
Responses
of a 15 gram (0.015kg) bullet tells me what I am looking for.
of a 15 gram (0.015kg) bullet tells me what I am looking for.
traveling at 280 m/s. tells me what I am looking for.
traveling at 280 m/s. tells me what I am looking for.
What is the momentum tells me what I am looking for.
Responses
of a 15 gram (0.015kg) bullet tells me what I am looking for.
of a 15 gram (0.015kg) bullet tells me what I am looking for.
traveling at 280 m/s. tells me what I am looking for.
traveling at 280 m/s. tells me what I am looking for.
What is the momentum tells me what I am looking for.
Answers
GPT-4o mini
To calculate the momentum of the bullet, we can use the formula:
\[
\text{Momentum} (p) = \text{mass} (m) \times \text{velocity} (v)
\]
Given:
- Mass of the bullet (m) = 0.015 kg
- Velocity of the bullet (v) = 280 m/s
Substituting the values into the formula:
\[
p = 0.015 \, \text{kg} \times 280 \, \text{m/s} = 4.2 \, \text{kg m/s}
\]
Thus, the momentum of the bullet is **4.2 kg m/s**.
\[
\text{Momentum} (p) = \text{mass} (m) \times \text{velocity} (v)
\]
Given:
- Mass of the bullet (m) = 0.015 kg
- Velocity of the bullet (v) = 280 m/s
Substituting the values into the formula:
\[
p = 0.015 \, \text{kg} \times 280 \, \text{m/s} = 4.2 \, \text{kg m/s}
\]
Thus, the momentum of the bullet is **4.2 kg m/s**.