Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
A parasail is 120 of a meter above the water. Then, after 10 minutes, the parasail is 150 of a meter above the water. What is t...Asked by Xxxenobia! From REALITY
A parasail is 1/20 of a meter above the water. Then, after 10 minutes, the parasail is 1/50 of a meter above the water. What is the change in height?(1 point)
Responses
1/20 meter
Start Fraction 1 over 20 End Fraction meter
7/100 meter
Start Fraction 7 over 100 End Fraction meter
1/50 meter
Start Fraction 1 over 50 End Fraction meter
3/100 meter
Responses
1/20 meter
Start Fraction 1 over 20 End Fraction meter
7/100 meter
Start Fraction 7 over 100 End Fraction meter
1/50 meter
Start Fraction 1 over 50 End Fraction meter
3/100 meter
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the change in height, we need to subtract the final height from the initial height.
1. Initial height: \( \frac{1}{20} \) meter
2. Final height: \( \frac{1}{50} \) meter
Now, we can calculate the change in height:
\[
\text{Change in height} = \text{Initial height} - \text{Final height} = \frac{1}{20} - \frac{1}{50}
\]
To subtract these fractions, we need a common denominator. The least common multiple of 20 and 50 is 100. We can convert both fractions:
\[
\frac{1}{20} = \frac{5}{100} \quad (\text{Multiply both numerator and denominator by 5})
\]
\[
\frac{1}{50} = \frac{2}{100} \quad (\text{Multiply both numerator and denominator by 2})
\]
Now we can perform the subtraction:
\[
\text{Change in height} = \frac{5}{100} - \frac{2}{100} = \frac{3}{100}
\]
Thus, the change in height is
\[
\frac{3}{100} \text{ meter.}
\]
So the correct answer is \( \frac{3}{100} \) meter.
1. Initial height: \( \frac{1}{20} \) meter
2. Final height: \( \frac{1}{50} \) meter
Now, we can calculate the change in height:
\[
\text{Change in height} = \text{Initial height} - \text{Final height} = \frac{1}{20} - \frac{1}{50}
\]
To subtract these fractions, we need a common denominator. The least common multiple of 20 and 50 is 100. We can convert both fractions:
\[
\frac{1}{20} = \frac{5}{100} \quad (\text{Multiply both numerator and denominator by 5})
\]
\[
\frac{1}{50} = \frac{2}{100} \quad (\text{Multiply both numerator and denominator by 2})
\]
Now we can perform the subtraction:
\[
\text{Change in height} = \frac{5}{100} - \frac{2}{100} = \frac{3}{100}
\]
Thus, the change in height is
\[
\frac{3}{100} \text{ meter.}
\]
So the correct answer is \( \frac{3}{100} \) meter.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.