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Identify the equivalent expression in the equation (1)/(x^(2)-x)+(1)/(x)=(5)/(x^(2)-x) and demonstrate multiplying by the commo...Question
Identify the equivalent expression in the equation 1/x^2-x+1/x=5/x^2-x and demonstrate multiplying by the common denominator
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GPT-4o mini
To identify the equivalent expression in the equation
\[
\frac{1}{x^2} - x + \frac{1}{x} = \frac{5}{x^2} - x
\]
we can start by eliminating the fractions by multiplying through by the common denominator, which in this case is \(x^2\).
Let's do that step-by-step.
1. **Identify the common denominator**: The common denominator for all terms in the equation is \(x^2\).
2. **Multiply the entire equation by \(x^2\)**:
\[
x^2 \left(\frac{1}{x^2}\right) - x^2(x) + x^2\left(\frac{1}{x}\right) = x^2\left(\frac{5}{x^2}\right) - x^2(x)
\]
3. **Distributing \(x^2\) across each term**:
- \(\frac{1}{x^2} \cdot x^2 = 1\)
- \(-x^2 \cdot x = -x^3\)
- \(\frac{1}{x} \cdot x^2 = x\)
- \(\frac{5}{x^2} \cdot x^2 = 5\)
- \(-x^2 \cdot x = -x^3\)
Putting it all together, we have:
\[
1 - x^3 + x = 5 - x^3
\]
4. **Now we can simplify the equation**:
Cancelling out \(-x^3\) from both sides, we get:
\[
1 + x = 5
\]
5. **Solving for \(x\)**:
Subtract \(1\) from both sides:
\[
x = 5 - 1 = 4
\]
Thus, the equivalent expression in the equation when we multiply by the common denominator is:
\[
1 - x^3 + x = 5 - x^3
\]
And the equation simplifies neatly to \(x = 4\).
\[
\frac{1}{x^2} - x + \frac{1}{x} = \frac{5}{x^2} - x
\]
we can start by eliminating the fractions by multiplying through by the common denominator, which in this case is \(x^2\).
Let's do that step-by-step.
1. **Identify the common denominator**: The common denominator for all terms in the equation is \(x^2\).
2. **Multiply the entire equation by \(x^2\)**:
\[
x^2 \left(\frac{1}{x^2}\right) - x^2(x) + x^2\left(\frac{1}{x}\right) = x^2\left(\frac{5}{x^2}\right) - x^2(x)
\]
3. **Distributing \(x^2\) across each term**:
- \(\frac{1}{x^2} \cdot x^2 = 1\)
- \(-x^2 \cdot x = -x^3\)
- \(\frac{1}{x} \cdot x^2 = x\)
- \(\frac{5}{x^2} \cdot x^2 = 5\)
- \(-x^2 \cdot x = -x^3\)
Putting it all together, we have:
\[
1 - x^3 + x = 5 - x^3
\]
4. **Now we can simplify the equation**:
Cancelling out \(-x^3\) from both sides, we get:
\[
1 + x = 5
\]
5. **Solving for \(x\)**:
Subtract \(1\) from both sides:
\[
x = 5 - 1 = 4
\]
Thus, the equivalent expression in the equation when we multiply by the common denominator is:
\[
1 - x^3 + x = 5 - x^3
\]
And the equation simplifies neatly to \(x = 4\).
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