what is the distance between carmen's house and the store/

carmen stopped at aplace located at the midpoint between school and home. Where did she stop?
coordintates are
carmens house. (8,2) and store is (7,5)
school is (4,4) Gym (6,3), store(7,5) and home is (8,2)

1 answer

To find the distance between Carmen's house and the store, you can use the distance formula:

\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]

For Carmen's house at (8, 2) and the store at (7, 5):

  • \(x_1 = 8\), \(y_1 = 2\)
  • \(x_2 = 7\), \(y_2 = 5\)

Plugging in the coordinates:

\[ d = \sqrt{(7 - 8)^2 + (5 - 2)^2} = \sqrt{(-1)^2 + (3)^2} = \sqrt{1 + 9} = \sqrt{10} \]

So, the distance between Carmen's house and the store is \(\sqrt{10}\), which is approximately 3.16 units.

Next, to find the midpoint between Carmen's house and school, you can use the midpoint formula:

\[ \text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \]

For Carmen's house at (8, 2) and school at (4, 4):

  • \(x_1 = 8\), \(y_1 = 2\)
  • \(x_2 = 4\), \(y_2 = 4\)

Calculating the midpoint:

\[ \text{Midpoint} = \left( \frac{8 + 4}{2}, \frac{2 + 4}{2} \right) = \left( \frac{12}{2}, \frac{6}{2} \right) = (6, 3) \]

Thus, Carmen stopped at the coordinates (6, 3), which is the location of the gym.