A basketball player is 6 and 2/3 ft tall his infant son is 1/4 as tall how tall is his son a 2 and 2/12 ft b 1 and 1/2 ft c 2 and 2/3 feet d 1 and 2/3 feet

Answer 1

To find the height of the basketball player's son, we need to calculate \( \frac{1}{4} \) of \( 6 \frac{2}{3} \) feet.

First, let's convert \( 6 \frac{2}{3} \) to an improper fraction:

\[ 6 \frac{2}{3} = 6 + \frac{2}{3} = \frac{18}{3} + \frac{2}{3} = \frac{20}{3} \]

Now, we can find \( \frac{1}{4} \) of \( \frac{20}{3} \):

\[ \text{Son's height} = \frac{1}{4} \times \frac{20}{3} = \frac{20}{12} = \frac{5}{3} \]

Now, \( \frac{5}{3} \) can be converted to a mixed number:

\[ \frac{5}{3} = 1 \frac{2}{3} \]

Thus, the height of the basketball player’s son is \( 1 \frac{2}{3} \) feet, so the answer is:

d 1 and 2/3 feet.