Question
A basketball player is 6 and 2/3 ft tall his infant son is 1/4 as tall how tall is his son a 2 and 2/12 ft b 1 and 1/2 ft c 2 and 2/3 feet d 1 and 2/3 feet
Answers
GPT-4o mini
To find the height of the basketball player's son, we need to calculate \( \frac{1}{4} \) of \( 6 \frac{2}{3} \) feet.
First, let's convert \( 6 \frac{2}{3} \) to an improper fraction:
\[
6 \frac{2}{3} = 6 + \frac{2}{3} = \frac{18}{3} + \frac{2}{3} = \frac{20}{3}
\]
Now, we can find \( \frac{1}{4} \) of \( \frac{20}{3} \):
\[
\text{Son's height} = \frac{1}{4} \times \frac{20}{3} = \frac{20}{12} = \frac{5}{3}
\]
Now, \( \frac{5}{3} \) can be converted to a mixed number:
\[
\frac{5}{3} = 1 \frac{2}{3}
\]
Thus, the height of the basketball player’s son is \( 1 \frac{2}{3} \) feet, so the answer is:
**d 1 and 2/3 feet**.
First, let's convert \( 6 \frac{2}{3} \) to an improper fraction:
\[
6 \frac{2}{3} = 6 + \frac{2}{3} = \frac{18}{3} + \frac{2}{3} = \frac{20}{3}
\]
Now, we can find \( \frac{1}{4} \) of \( \frac{20}{3} \):
\[
\text{Son's height} = \frac{1}{4} \times \frac{20}{3} = \frac{20}{12} = \frac{5}{3}
\]
Now, \( \frac{5}{3} \) can be converted to a mixed number:
\[
\frac{5}{3} = 1 \frac{2}{3}
\]
Thus, the height of the basketball player’s son is \( 1 \frac{2}{3} \) feet, so the answer is:
**d 1 and 2/3 feet**.