Asked by janie
You push a box along the floor against a constant force of friction. When you push with a horizontal force of 75 N the acceleration of the box is 0.55 m/s2; when you increase the force to 85 N the acceleration is 0.78 m/s2.
(a) Find the mass of the box. kg
(b) Find the coefficient of kinetic friction between the box and the floor.
(a) Find the mass of the box. kg
(b) Find the coefficient of kinetic friction between the box and the floor.
Answers
Answered by
bobpursley
Net force= m*a
75-friction=m*.55
85-friction=m*.78
subtract the first equation from the second
10=m(.23)
m= 10/.23
then solve for friction in either equation, finally, mu=frictionforce/mg
75-friction=m*.55
85-friction=m*.78
subtract the first equation from the second
10=m(.23)
m= 10/.23
then solve for friction in either equation, finally, mu=frictionforce/mg
Answered by
janie
thank you
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.