Asked by DL
Using rational approximations, what is an inequality statement comparing square root 81 and square root 88? Enter <, >, or =
Answers
Answered by
GPT-4o mini
To compare \(\sqrt{81}\) and \(\sqrt{88}\), we can calculate the square roots:
\[
\sqrt{81} = 9
\]
Next, we approximate \(\sqrt{88}\). We know that:
- \(\sqrt{81} = 9\)
- \(\sqrt{100} = 10\)
Since \(88\) is between \(81\) and \(100\), we can deduce that \(\sqrt{88}\) is between \(9\) and \(10\). To estimate further, we can check the squares of numbers closer to \(88\):
- \(9.3^2 = 86.49\)
- \(9.4^2 = 88.36\)
This shows that \(\sqrt{88}\) is between \(9.3\) and \(9.4\), but closer to \(9.4\).
Thus, we can conclude:
\[
\sqrt{81} < \sqrt{88}
\]
Therefore, the inequality statement comparing \(\sqrt{81}\) and \(\sqrt{88}\) is:
\[
\sqrt{81} < \sqrt{88}
\]
So the answer is:
<
\[
\sqrt{81} = 9
\]
Next, we approximate \(\sqrt{88}\). We know that:
- \(\sqrt{81} = 9\)
- \(\sqrt{100} = 10\)
Since \(88\) is between \(81\) and \(100\), we can deduce that \(\sqrt{88}\) is between \(9\) and \(10\). To estimate further, we can check the squares of numbers closer to \(88\):
- \(9.3^2 = 86.49\)
- \(9.4^2 = 88.36\)
This shows that \(\sqrt{88}\) is between \(9.3\) and \(9.4\), but closer to \(9.4\).
Thus, we can conclude:
\[
\sqrt{81} < \sqrt{88}
\]
Therefore, the inequality statement comparing \(\sqrt{81}\) and \(\sqrt{88}\) is:
\[
\sqrt{81} < \sqrt{88}
\]
So the answer is:
<
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