Asked by DL
The height of an equilateral triangle equals 3 square root over 2 times thecide link uSing 7 over 4 for the √3.What is the approximate height in meters of an equal letter triangle with a side length of eight meters
Answers
Answered by
GPT-4o mini
To find the height of an equilateral triangle, we can use the formula for the height \( h \) of an equilateral triangle in terms of its side length \( s \):
\[
h = \frac{\sqrt{3}}{2} s
\]
In this case, we are given that \( \sqrt{3} \) can be approximated as \( \frac{7}{4} \).
Now, substituting \( \frac{7}{4} \) for \( \sqrt{3} \) and the side length \( s = 8 \) meters:
\[
h = \frac{7}{4} \cdot \frac{1}{2} \cdot 8
\]
Calculating this step-by-step:
1. First, simplify \( \frac{1}{2} \cdot 8 \):
\[
\frac{1}{2} \cdot 8 = 4
\]
2. Now, multiply by \( \frac{7}{4} \):
\[
h = \frac{7}{4} \cdot 4
\]
3. Simplifying this gives:
\[
h = 7 \text{ meters}
\]
Thus, the approximate height of the equilateral triangle with a side length of 8 meters is **7 meters**.
\[
h = \frac{\sqrt{3}}{2} s
\]
In this case, we are given that \( \sqrt{3} \) can be approximated as \( \frac{7}{4} \).
Now, substituting \( \frac{7}{4} \) for \( \sqrt{3} \) and the side length \( s = 8 \) meters:
\[
h = \frac{7}{4} \cdot \frac{1}{2} \cdot 8
\]
Calculating this step-by-step:
1. First, simplify \( \frac{1}{2} \cdot 8 \):
\[
\frac{1}{2} \cdot 8 = 4
\]
2. Now, multiply by \( \frac{7}{4} \):
\[
h = \frac{7}{4} \cdot 4
\]
3. Simplifying this gives:
\[
h = 7 \text{ meters}
\]
Thus, the approximate height of the equilateral triangle with a side length of 8 meters is **7 meters**.