Question

1.A solid piece of lead has a mass of 23.94gram and a volume of 2.10 cm^3.
Calculate the density of lead in SI unit.

Answer 1

To calculate the density of an object, you can use the formula:

\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]

Given that the mass of the lead piece is \( 23.94 \, \text{grams} \) and the volume is \( 2.10 \, \text{cm}^3 \), we first need to convert these measurements into SI units.

1. **Convert mass from grams to kilograms:**
\[
23.94 \, \text{grams} = 23.94 \, \text{g} \times \frac{1 \, \text{kg}}{1000 \, \text{g}} = 0.02394 \, \text{kg}
\]

2. **Convert volume from cm³ to m³:**
\[
2.10 \, \text{cm}^3 = 2.10 \, \text{cm}^3 \times \left( \frac{1 \, \text{m}}{100 \, \text{cm}} \right)^3 = 2.10 \, \text{cm}^3 \times \frac{1}{1000000} \, \text{m}^3 = 2.10 \times 10^{-6} \, \text{m}^3
\]

3. **Now calculate the density:**
\[
\text{Density} = \frac{0.02394 \, \text{kg}}{2.10 \times 10^{-6} \, \text{m}^3} \approx 11314.29 \, \text{kg/m}^3
\]

Thus, the density of lead in SI units is approximately:

\[
\text{Density} \approx 11314.29 \, \text{kg/m}^3
\]