Question
Find the domain of the function. f(x)= 2x+1/ x^2+x-20 (Enter your answer using interval notation.)
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Answered by
GPT-4o mini
To find the domain of the function \( f(x) = \frac{2x + 1}{x^2 + x - 20} \), we need to determine the values of \( x \) for which the function is defined. The function will be undefined wherever the denominator is zero.
First, let's find the values for which the denominator \( x^2 + x - 20 \) is zero. We can factor the quadratic expression:
\[
x^2 + x - 20 = (x - 4)(x + 5)
\]
Now, set the factored form equal to zero:
\[
(x - 4)(x + 5) = 0
\]
This gives us two solutions:
\[
x - 4 = 0 \implies x = 4
\]
\[
x + 5 = 0 \implies x = -5
\]
Thus, the function \( f(x) \) is undefined at \( x = 4 \) and \( x = -5 \).
To find the domain, we need to exclude these values from the set of all real numbers. Therefore, the domain in interval notation is:
\[
(-\infty, -5) \cup (-5, 4) \cup (4, \infty)
\]
In summary, the domain of the function \( f(x) \) is
\[
(-\infty, -5) \cup (-5, 4) \cup (4, \infty).
\]
First, let's find the values for which the denominator \( x^2 + x - 20 \) is zero. We can factor the quadratic expression:
\[
x^2 + x - 20 = (x - 4)(x + 5)
\]
Now, set the factored form equal to zero:
\[
(x - 4)(x + 5) = 0
\]
This gives us two solutions:
\[
x - 4 = 0 \implies x = 4
\]
\[
x + 5 = 0 \implies x = -5
\]
Thus, the function \( f(x) \) is undefined at \( x = 4 \) and \( x = -5 \).
To find the domain, we need to exclude these values from the set of all real numbers. Therefore, the domain in interval notation is:
\[
(-\infty, -5) \cup (-5, 4) \cup (4, \infty)
\]
In summary, the domain of the function \( f(x) \) is
\[
(-\infty, -5) \cup (-5, 4) \cup (4, \infty).
\]
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