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use the distributive property to rewrite the polynomials (x+4) (x-6)Asked by Yes.
use the Distributive Property to rewrite the polynomial (x+8)(x−2)
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Answered by
GPT-4o mini
To rewrite the polynomial \((x + 8)(x - 2)\) using the Distributive Property, you'll distribute each term in the first parenthesis by each term in the second parenthesis.
Here's how you do it step by step:
1. Distribute \(x\) to both terms in the second parenthesis:
\[
x \cdot (x - 2) = x^2 - 2x
\]
2. Distribute \(8\) to both terms in the second parenthesis:
\[
8 \cdot (x - 2) = 8x - 16
\]
3. Now combine the results from both distributions:
\[
x^2 - 2x + 8x - 16
\]
4. Combine like terms (\(-2x + 8x\)):
\[
x^2 + 6x - 16
\]
So, the polynomial \((x + 8)(x - 2)\) can be rewritten as:
\[
x^2 + 6x - 16
\]
Here's how you do it step by step:
1. Distribute \(x\) to both terms in the second parenthesis:
\[
x \cdot (x - 2) = x^2 - 2x
\]
2. Distribute \(8\) to both terms in the second parenthesis:
\[
8 \cdot (x - 2) = 8x - 16
\]
3. Now combine the results from both distributions:
\[
x^2 - 2x + 8x - 16
\]
4. Combine like terms (\(-2x + 8x\)):
\[
x^2 + 6x - 16
\]
So, the polynomial \((x + 8)(x - 2)\) can be rewritten as:
\[
x^2 + 6x - 16
\]
Answered by
GPT-4o mini
To rewrite the expression \(3x(x + 3)\) using the Distributive Property, you'll distribute \(3x\) to each term inside the parentheses:
1. Distribute \(3x\) to the first term \(x\):
\[
3x \cdot x = 3x^2
\]
2. Distribute \(3x\) to the second term \(3\):
\[
3x \cdot 3 = 9x
\]
3. Combine the results from both distributions:
\[
3x^2 + 9x
\]
Thus, the expression \(3x(x + 3)\) can be rewritten as:
\[
3x^2 + 9x
\]
1. Distribute \(3x\) to the first term \(x\):
\[
3x \cdot x = 3x^2
\]
2. Distribute \(3x\) to the second term \(3\):
\[
3x \cdot 3 = 9x
\]
3. Combine the results from both distributions:
\[
3x^2 + 9x
\]
Thus, the expression \(3x(x + 3)\) can be rewritten as:
\[
3x^2 + 9x
\]
Answered by
GPT-4o mini
To find the product of the polynomials \((2x + 1)(x - 4)\), we will use the Distributive Property (also known as the FOIL method for binomials):
1. **First**: Multiply the first terms:
\[
2x \cdot x = 2x^2
\]
2. **Outer**: Multiply the outer terms:
\[
2x \cdot (-4) = -8x
\]
3. **Inner**: Multiply the inner terms:
\[
1 \cdot x = 1x = x
\]
4. **Last**: Multiply the last terms:
\[
1 \cdot (-4) = -4
\]
Now, combine all these results:
\[
2x^2 - 8x + x - 4
\]
Combine the like terms (\(-8x\) and \(x\)):
\[
2x^2 - 7x - 4
\]
Thus, the product of the polynomials \((2x + 1)(x - 4)\) is:
\[
2x^2 - 7x - 4
\]
1. **First**: Multiply the first terms:
\[
2x \cdot x = 2x^2
\]
2. **Outer**: Multiply the outer terms:
\[
2x \cdot (-4) = -8x
\]
3. **Inner**: Multiply the inner terms:
\[
1 \cdot x = 1x = x
\]
4. **Last**: Multiply the last terms:
\[
1 \cdot (-4) = -4
\]
Now, combine all these results:
\[
2x^2 - 8x + x - 4
\]
Combine the like terms (\(-8x\) and \(x\)):
\[
2x^2 - 7x - 4
\]
Thus, the product of the polynomials \((2x + 1)(x - 4)\) is:
\[
2x^2 - 7x - 4
\]
Answered by
GPT-4o mini
Let's go through the multiplication of the polynomials \((2x + 1)(x - 4)\) step by step again:
Using the Distributive Property (or FOIL for binomials):
1. **First**: Multiply the first terms:
\[
2x \cdot x = 2x^2
\]
2. **Outer**: Multiply the outer terms:
\[
2x \cdot (-4) = -8x
\]
3. **Inner**: Multiply the inner terms:
\[
1 \cdot x = 1x = x
\]
4. **Last**: Multiply the last terms:
\[
1 \cdot (-4) = -4
\]
Now, combine all these results:
\[
2x^2 - 8x + x - 4
\]
Now, combine the like terms (\(-8x\) and \(x\)):
\[
2x^2 - 7x - 4
\]
So the product of the polynomials \((2x + 1)(x - 4)\) is:
\[
2x^2 - 7x - 4
\]
Thus, my previous calculation was indeed correct. The resulting polynomial contains both positive and negative terms based on the multiplication steps shown above. If you have a specific aspect about it that you'd like to clarify, please let me know!
Using the Distributive Property (or FOIL for binomials):
1. **First**: Multiply the first terms:
\[
2x \cdot x = 2x^2
\]
2. **Outer**: Multiply the outer terms:
\[
2x \cdot (-4) = -8x
\]
3. **Inner**: Multiply the inner terms:
\[
1 \cdot x = 1x = x
\]
4. **Last**: Multiply the last terms:
\[
1 \cdot (-4) = -4
\]
Now, combine all these results:
\[
2x^2 - 8x + x - 4
\]
Now, combine the like terms (\(-8x\) and \(x\)):
\[
2x^2 - 7x - 4
\]
So the product of the polynomials \((2x + 1)(x - 4)\) is:
\[
2x^2 - 7x - 4
\]
Thus, my previous calculation was indeed correct. The resulting polynomial contains both positive and negative terms based on the multiplication steps shown above. If you have a specific aspect about it that you'd like to clarify, please let me know!
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