To analyze the statement that the product of a multiplication problem is \( \sqrt{225} \), we start by calculating \( \sqrt{225} \):
\[ \sqrt{225} = 15 \]
This value, 15, is a rational number.
In multiplication, the product of two factors can be rational or irrational based on the nature of the factors. Let's examine the options given:
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They are both rational because the product is rational.
This is indeed a possibility. If both factors are rational numbers, the product will also be rational. This choice can be true. -
One factor is rational and the other irrational.
This is also possible. For example, \( \sqrt{225} = 15 \) could be expressed as \( 5 \times 3 \) (both factors rational) or as \( \sqrt{9} \times \sqrt{25} \) (also rational). You could also express it as \( 15 \times 1 \) (both rational), or some familiar irrational times a rational could yield 15, yet still not exceed rationality. But in the general multiplication sense, this is not a necessity. -
At least one factor is irrational because the product is irrational.
This is incorrect, since we have established that \( \sqrt{225} = 15 \) is rational. -
It cannot be predicted.
Not true here, since we know the product is rational.
Since we have a rational product (15), the most valid conclusion is:
1. They are both rational because the product is rational.
However, note that while option 2 could be true in another multiplicative scenario, option 1 directly concludes from the evidence presented. Factors may lead to a mixture of rational and irrational possibilities, but under a product of \( \sqrt{225} \), they comfortably lead back to being rational factors predominantly. So the best answer remains option 1.