To find out what integer \( n \) is close to \( \frac{9}{4} \) in terms of its square root, we can first calculate \( \frac{9}{4} \):
\[ \frac{9}{4} = 2.25 \]
Next, we want to find an integer \( n \) such that:
\[ \sqrt{n} \approx 2.25 \]
To find \( n \), we can square \( 2.25 \):
\[ n = (2.25)^2 \]
Calculating \( (2.25)^2 \):
\[ (2.25)^2 = 5.0625 \]
Since \( n \) needs to be an integer, we can round \( 5.0625 \) to the nearest integer, which is \( 5 \).
Now let's confirm that \( \sqrt{5} \) is indeed close to \( 2.25 \):
Calculating \( \sqrt{5} \):
\[ \sqrt{5} \approx 2.236 \]
Since \( 2.236 \) is indeed close to \( 2.25 \), we conclude that \( n \) is:
\[ \boxed{5} \]
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