To find an integer whose square root is close to \( \frac{9}{4} \), we first calculate the square of \( \frac{9}{4} \):
\[ \left( \frac{9}{4} \right)^2 = \frac{9^2}{4^2} = \frac{81}{16} \]
Now, we need to simplify \( \frac{81}{16} \):
\[ \frac{81}{16} \approx 5.0625 \]
Since we are looking for the closest integer, we can round \( 5.0625 \) to the nearest whole number. The integer closest to \( 5.0625 \) is \( 5 \).
Thus, \( \frac{9}{4} \) is close to the square root of \( 5 \).
In conclusion, \( \frac{9}{4} \) is close to the square root of the integer \( 5 \).
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