Asked by Cole
In a special local election, one candidate received 288 votes less than twice the number of votes of the opponent. How many votes did each candidate receive if the total number of votes in the election is 136,395?
Answers
Answered by
bobpursley
OC=2OP-288
OC+OP=136,395
OC+OP=136,395
Answered by
Cole
I don't understand this equation that you have here?
Answered by
bobpursley
Those equations are what the problem states, that is all. OC is the one candiadate, OP is the opposing candidate.
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