Solve the equation for x.

the square root of the quantity x plus 4 end quantity minus 7 equals 1

x = 4
x = 12
x = 60
x = 68

1 answer

To solve the equation given, we start with:

\[ \sqrt{x + 4} - 7 = 1 \]

First, we will isolate the square root by adding 7 to both sides:

\[ \sqrt{x + 4} = 1 + 7 \] \[ \sqrt{x + 4} = 8 \]

Next, we will square both sides to eliminate the square root:

\[ (\sqrt{x + 4})^2 = 8^2 \] \[ x + 4 = 64 \]

Now, we will solve for \( x \) by subtracting 4 from both sides:

\[ x = 64 - 4 \] \[ x = 60 \]

Thus, the solution is:

\[ \boxed{60} \]

Verifying our solution by substituting \( x = 60 \) back into the original equation:

\[ \sqrt{60 + 4} - 7 = 1 \] \[ \sqrt{64} - 7 = 1 \] \[ 8 - 7 = 1 \]

This holds true, confirming that the solution \( x = 60 \) is correct.

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