Question
Solve the equation for x.
the square root of the quantity x plus 4 end quantity minus 7 equals 1
x = 4
x = 12
x = 60
x = 68
the square root of the quantity x plus 4 end quantity minus 7 equals 1
x = 4
x = 12
x = 60
x = 68
Answers
GPT-4o mini
To solve the equation given, we start with:
\[
\sqrt{x + 4} - 7 = 1
\]
First, we will isolate the square root by adding 7 to both sides:
\[
\sqrt{x + 4} = 1 + 7
\]
\[
\sqrt{x + 4} = 8
\]
Next, we will square both sides to eliminate the square root:
\[
(\sqrt{x + 4})^2 = 8^2
\]
\[
x + 4 = 64
\]
Now, we will solve for \( x \) by subtracting 4 from both sides:
\[
x = 64 - 4
\]
\[
x = 60
\]
Thus, the solution is:
\[
\boxed{60}
\]
Verifying our solution by substituting \( x = 60 \) back into the original equation:
\[
\sqrt{60 + 4} - 7 = 1
\]
\[
\sqrt{64} - 7 = 1
\]
\[
8 - 7 = 1
\]
This holds true, confirming that the solution \( x = 60 \) is correct.
\[
\sqrt{x + 4} - 7 = 1
\]
First, we will isolate the square root by adding 7 to both sides:
\[
\sqrt{x + 4} = 1 + 7
\]
\[
\sqrt{x + 4} = 8
\]
Next, we will square both sides to eliminate the square root:
\[
(\sqrt{x + 4})^2 = 8^2
\]
\[
x + 4 = 64
\]
Now, we will solve for \( x \) by subtracting 4 from both sides:
\[
x = 64 - 4
\]
\[
x = 60
\]
Thus, the solution is:
\[
\boxed{60}
\]
Verifying our solution by substituting \( x = 60 \) back into the original equation:
\[
\sqrt{60 + 4} - 7 = 1
\]
\[
\sqrt{64} - 7 = 1
\]
\[
8 - 7 = 1
\]
This holds true, confirming that the solution \( x = 60 \) is correct.
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