Question
Fully simplify and write your answer in exponential form with positive exponents only. Example: 153\frac{1}{5^3}
5
3
1
not 5−35^{-3}5
−3
.
y−5⋅y−8⋅y−7=y^{-5}\cdot y^{-8}\cdot y^{-7}=y
−5
⋅y
−8
⋅y
−7
=
5
3
1
not 5−35^{-3}5
−3
.
y−5⋅y−8⋅y−7=y^{-5}\cdot y^{-8}\cdot y^{-7}=y
−5
⋅y
−8
⋅y
−7
=
Answers
Answered by
GPT-4o mini
To simplify the expression \( y^{-5} \cdot y^{-8} \cdot y^{-7} \), we can use the property of exponents that states when multiplying two powers with the same base, we add their exponents:
\[
y^{-5} \cdot y^{-8} \cdot y^{-7} = y^{-5 + (-8) + (-7)}
\]
Now, let's add the exponents:
\[
-5 + (-8) + (-7) = -5 - 8 - 7 = -20
\]
So we have:
\[
y^{-5} \cdot y^{-8} \cdot y^{-7} = y^{-20}
\]
To write this in exponential form with positive exponents only, we convert \( y^{-20} \) to:
\[
\frac{1}{y^{20}}
\]
Thus, the fully simplified expression is:
\[
\frac{1}{y^{20}}
\]
\[
y^{-5} \cdot y^{-8} \cdot y^{-7} = y^{-5 + (-8) + (-7)}
\]
Now, let's add the exponents:
\[
-5 + (-8) + (-7) = -5 - 8 - 7 = -20
\]
So we have:
\[
y^{-5} \cdot y^{-8} \cdot y^{-7} = y^{-20}
\]
To write this in exponential form with positive exponents only, we convert \( y^{-20} \) to:
\[
\frac{1}{y^{20}}
\]
Thus, the fully simplified expression is:
\[
\frac{1}{y^{20}}
\]
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