Question
ind the product of (4y+5)(4y−4)
in standard form. You can use the Algebra tiles to help you.(1 point)
Responses
8y+1
8 y plus 1
−16y2+20y−4
negative 16 y squared plus 20 y minus 4
16y2+4y−20
16 y squared plus 4 y minus 20
−20+4y+16y2
negative 20 plus 4 y plus 16 y squared
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in standard form. You can use the Algebra tiles to help you.(1 point)
Responses
8y+1
8 y plus 1
−16y2+20y−4
negative 16 y squared plus 20 y minus 4
16y2+4y−20
16 y squared plus 4 y minus 20
−20+4y+16y2
negative 20 plus 4 y plus 16 y squared
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Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the product of \((4y + 5)(4y - 4)\), we can use the distributive property (also known as the FOIL method for binomials).
We perform the multiplication step by step:
1. **First**: Multiply the first terms:
\[
4y \cdot 4y = 16y^2
\]
2. **Outer**: Multiply the outer terms:
\[
4y \cdot (-4) = -16y
\]
3. **Inner**: Multiply the inner terms:
\[
5 \cdot 4y = 20y
\]
4. **Last**: Multiply the last terms:
\[
5 \cdot (-4) = -20
\]
Now, we can combine these results:
\[
16y^2 - 16y + 20y - 20
\]
Combine like terms:
\[
16y^2 + (20y - 16y) - 20 = 16y^2 + 4y - 20
\]
So, the product in standard form is:
\[
16y^2 + 4y - 20
\]
The correct response from your options is:
**16y² + 4y - 20**.
We perform the multiplication step by step:
1. **First**: Multiply the first terms:
\[
4y \cdot 4y = 16y^2
\]
2. **Outer**: Multiply the outer terms:
\[
4y \cdot (-4) = -16y
\]
3. **Inner**: Multiply the inner terms:
\[
5 \cdot 4y = 20y
\]
4. **Last**: Multiply the last terms:
\[
5 \cdot (-4) = -20
\]
Now, we can combine these results:
\[
16y^2 - 16y + 20y - 20
\]
Combine like terms:
\[
16y^2 + (20y - 16y) - 20 = 16y^2 + 4y - 20
\]
So, the product in standard form is:
\[
16y^2 + 4y - 20
\]
The correct response from your options is:
**16y² + 4y - 20**.
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