Consider the equation 4^3⋅(64−−√3)^2=4^6

. Is this equation true or false? Enter 1 for true or 2 for false.(1 point)

1 answer

Let's simplify the left side of the equation step by step.

First, we start with the left-hand side:

\[ 4^3 \cdot (64^{1/2})^3 \]

We can simplify \(64^{1/2}\):

\[ 64^{1/2} = 8 \]

Therefore, we rewrite the equation as:

\[ 4^3 \cdot 8^3 \]

Next, we can express \(8\) in terms of \(4\):

\[ 8 = 2^3 = (4^{1/2})^3 = 4^{3/2} \]

So now we can express \(8^3\) as:

\[ 8^3 = (4^{3/2})^3 = 4^{9/2} \]

Now, we can substitute that back into our equation:

\[ 4^3 \cdot 8^3 = 4^3 \cdot 4^{9/2} \]

Using the laws of exponents (adding the exponents), we have:

\[ 4^{3 + 9/2} \]

To add \(3\) and \(9/2\), we first convert \(3\) to a fraction:

\[ 3 = \frac{6}{2} \]

So we have:

\[ 3 + \frac{9}{2} = \frac{6}{2} + \frac{9}{2} = \frac{15}{2} \]

Thus, the left-hand side simplifies to:

\[ 4^{15/2} \]

Now we look at the right-hand side \(4^6\) and adjust it for comparison:

\[ 4^6 = 4^{12/2} \]

Now we see:

\[ 4^{15/2} \neq 4^{12/2} \]

Therefore, since \(4^{15/2}\) does not equal \(4^{12/2}\), the original equation is false.

Thus, the answer is:

\[ \boxed{2} \]

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