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The area of a rectangle is calculated with the formula A=lw . If the area of a rectangle is 52.5 m2 and the width is 5 m, what is the length? Explain the solution to the real-world problem.(1 point)
Responses
l=10.5
l equals 10.5
The length is 262.5 m2.
The length is 262.5 m squared .
The length is 262.5 m.
The length is 262.5 m.
The length is 10.5 m.
The length is 10.5 m.
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Answered by
GPT-4o mini
To find the length of the rectangle, we can use the formula for the area of a rectangle:
\[ A = l \times w \]
where \( A \) is the area, \( l \) is the length, and \( w \) is the width.
We are given:
- The area \( A = 52.5 \, \text{m}^2 \)
- The width \( w = 5 \, \text{m} \)
We need to find the length \( l \).
We can rearrange the formula to solve for \( l \):
\[
l = \frac{A}{w}
\]
Substituting in the values we have:
\[
l = \frac{52.5 \, \text{m}^2}{5 \, \text{m}}
\]
Now, performing the calculation:
\[
l = 10.5 \, \text{m}
\]
So the length of the rectangle is \( 10.5 \, \text{m} \).
The correct response is:
**The length is 10.5 m.**
This means that with a width of 5 m and an area of 52.5 m², the length of the rectangle must be 10.5 meters.
\[ A = l \times w \]
where \( A \) is the area, \( l \) is the length, and \( w \) is the width.
We are given:
- The area \( A = 52.5 \, \text{m}^2 \)
- The width \( w = 5 \, \text{m} \)
We need to find the length \( l \).
We can rearrange the formula to solve for \( l \):
\[
l = \frac{A}{w}
\]
Substituting in the values we have:
\[
l = \frac{52.5 \, \text{m}^2}{5 \, \text{m}}
\]
Now, performing the calculation:
\[
l = 10.5 \, \text{m}
\]
So the length of the rectangle is \( 10.5 \, \text{m} \).
The correct response is:
**The length is 10.5 m.**
This means that with a width of 5 m and an area of 52.5 m², the length of the rectangle must be 10.5 meters.
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