When solving the problem 4 ^ (5x - 3) = 16 ^ (x + 6) your friend does the following 4 ^ (5x - 3) = 4 ^ (x + 6); 5x - 3 = x + 6; 4x = 9; x = 9/4 Was this correct?

1 answer

Let's analyze your friend's solution step by step:

The original equation is:

\[ 4^{(5x - 3)} = 16^{(x + 6)} \]

First, we can express \(16\) as \(4^2\):

\[ 16^{(x + 6)} = (4^2)^{(x + 6)} \]

Using the power of a power rule \((a^m)^n = a^{m \cdot n}\), we can rewrite it:

\[ (4^2)^{(x + 6)} = 4^{2(x + 6)} \]

Now we can rewrite the equation:

\[ 4^{(5x - 3)} = 4^{2(x + 6)} \]

Since the bases are the same (both sides are powers of 4), we can set the exponents equal to each other:

\[ 5x - 3 = 2(x + 6) \]

Now, let's distribute on the right side:

\[ 5x - 3 = 2x + 12 \]

Next, we isolate \(x\). Subtract \(2x\) from both sides:

\[ 5x - 2x - 3 = 12 \]

This simplifies to:

\[ 3x - 3 = 12 \]

Now add 3 to both sides:

\[ 3x = 15 \]

Finally, divide by 3:

\[ x = 5 \]

So your friend made an error when simplifying the equation. The correct solution is:

\[ x = 5 \]

In conclusion, your friend's answer of \(x = \frac{9}{4}\) is incorrect.