Question

Solve the inequality 6x+1<5x−8

Answer 1

x_____ ______

whats the missing numbers

Answer 2

To solve the inequality \( 6x + 1 < 5x - 8 \), follow these steps:

1. **Subtract \( 5x \) from both sides:**

\[
6x - 5x + 1 < -8
\]

This simplifies to:

\[
x + 1 < -8
\]

2. **Subtract 1 from both sides:**

\[
x < -8 - 1
\]

Thus,

\[
x < -9
\]

So, the solution to the inequality \( 6x + 1 < 5x - 8 \) is:

\[
\boxed{x < -9}
\]

Answer 3

The inequality \( x < -9 \) means that \( x \) can take any value less than \(-9\).

If you're looking for the range of numbers that satisfy \( x < -9 \), it would be all real numbers less than \(-9\). This includes numbers like \(-10, -11, -12, \ldots\) and so on.

If you're looking for specific numbers to fill in the blanks in your format \( x\_\_\_\_\_\_\_\_\_\) based on the expression \( x < -9 \), here is a possible way to represent it:

\[
x < -9
\]

This implies:

- \( x < -10 \) (true, since any number less than -9 is valid)
- \( x < -8 \) (false, this number is not acceptable as it is not less than -9)

If you need specific values, you could say:

\[
x < -9 : \quad -10, -11, -12, \ldots
\]

However, if you meant something else or a specific format, please clarify!