Solve the inequality 6x+1<5x−8

3 answers

To solve the inequality \( 6x + 1 < 5x - 8 \), follow these steps:

  1. Subtract \( 5x \) from both sides:

    \[ 6x - 5x + 1 < -8 \]

    This simplifies to:

    \[ x + 1 < -8 \]

  2. Subtract 1 from both sides:

    \[ x < -8 - 1 \]

    Thus,

    \[ x < -9 \]

So, the solution to the inequality \( 6x + 1 < 5x - 8 \) is:

\[ \boxed{x < -9} \]

x_____ ______

whats the missing numbers

The inequality \( x < -9 \) means that \( x \) can take any value less than \(-9\).

If you're looking for the range of numbers that satisfy \( x < -9 \), it would be all real numbers less than \(-9\). This includes numbers like \(-10, -11, -12, \ldots\) and so on.

If you're looking for specific numbers to fill in the blanks in your format \( x_________\) based on the expression \( x < -9 \), here is a possible way to represent it:

\[ x < -9 \]

This implies:

  • \( x < -10 \) (true, since any number less than -9 is valid)
  • \( x < -8 \) (false, this number is not acceptable as it is not less than -9)

If you need specific values, you could say:

\[ x < -9 : \quad -10, -11, -12, \ldots \]

However, if you meant something else or a specific format, please clarify!

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