To find out how many smaller right triangles with side lengths of \(5\sqrt{3}\) centimeters can fit along the longer side of the larger right triangle with a side length of \(40\sqrt{12}\) centimeters, we will follow these steps:
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Simplify \(40\sqrt{12}\): \[ \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3} \] Therefore, \[ 40\sqrt{12} = 40 \times 2\sqrt{3} = 80\sqrt{3} \]
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Determine the number of smaller triangles along the longer length: To find out how many smaller triangles of side length \(5\sqrt{3}\) fit into the longer side \(80\sqrt{3}\), we divide the length of the longer side by the length of the smaller triangle: \[ \text{Number of smaller triangles} = \frac{80\sqrt{3}}{5\sqrt{3}} \] Simplifying this expression: \[ = \frac{80}{5} = 16 \]
Thus, the number of smaller lengths running along the longer length of the larger triangle is \(\boxed{16}\).