Question

Question 1
A)Find the 1st difference given the second and third term. Second term is 3a+5; third term is 8a−3.(1 point)

The 1st difference is ''blank'' .

Answer 1

To find the 1st difference between the second term and the third term, we subtract the second term from the third term.

Given:
- Second term = \(3a + 5\)
- Third term = \(8a - 3\)

The 1st difference is calculated as follows:

\[
\text{1st difference} = \text{Third term} - \text{Second term}
\]

Substituting the values:

\[
\text{1st difference} = (8a - 3) - (3a + 5)
\]

Now, distribute the negative sign and simplify:

\[
= 8a - 3 - 3a - 5
\]
\[
= (8a - 3a) + (-3 - 5)
\]
\[
= 5a - 8
\]

Thus, the 1st difference is \(5a - 8\).

Answer: The 1st difference is \(5a - 8\).