Question

Find the perimeter of a square with a side length of 212−−√
. Your answer must be in simplest radical form.(1 point)
Responses

163–√
16 square root of 3

812−−√
8 square root of 12

848−−√
8 square root of 48

323–√

Answers

Answered by GPT-4o mini
To find the perimeter of a square, we use the formula:

\[
\text{Perimeter} = 4 \times \text{side length}
\]

Given the side length is \( \sqrt{212} \), we can substitute this value into the formula:

\[
\text{Perimeter} = 4 \times \sqrt{212}
\]

Next, we can simplify \( \sqrt{212} \):

\[
\sqrt{212} = \sqrt{4 \times 53} = \sqrt{4} \times \sqrt{53} = 2\sqrt{53}
\]

Now substituting back into the perimeter formula:

\[
\text{Perimeter} = 4 \times 2\sqrt{53} = 8\sqrt{53}
\]

Thus, the perimeter of the square is:

\[
\boxed{8\sqrt{53}}
\]

Please note that this answer does not match any of the provided options, which may indicate a misunderstanding. However, based on the calculations, the correct simplest radical form for the perimeter given the side length is indeed \( 8\sqrt{53} \).
Answer
use the closest option given
Answered by GPT-4o mini
To match the perimeter calculation \(8\sqrt{53}\) to the closest option given, let's evaluate each one:

1. **Option: \(8\sqrt{12}\)**
- Simplifying \(8\sqrt{12}\):
\[
8\sqrt{12} = 8 \times \sqrt{4 \times 3} = 8 \times 2\sqrt{3} = 16\sqrt{3}
\]

2. **Option: \(8\sqrt{48}\)**
- Simplifying \(8\sqrt{48}\):
\[
8\sqrt{48} = 8 \times \sqrt{16 \times 3} = 8 \times 4\sqrt{3} = 32\sqrt{3}
\]

3. **Option: \(\sqrt{323}\)**
- This does not directly relate to our calculation since it’s not in the form of \(a\sqrt{b}\).

4. **Option: \(16\sqrt{3}\)** (Already simplified)
- As shown above, it simplifies to \(16\sqrt{3}\).

Comparing \(8\sqrt{53}\):

To approximate \( \sqrt{53} \):
- \(\sqrt{53} \approx 7.28\)
- Thus, \(8\sqrt{53} \approx 8 \times 7.28 \approx 58.24\).

We don't have an exact match, but we can quickly estimate:
- \(16\sqrt{3} \approx 16 \times 1.73 \approx 27.68\)
- \(32\sqrt{3} \approx 32 \times 1.73 \approx 55.36\)

Given the approximations, \(8\sqrt{48}\) aligns closest with \(8\sqrt{53}\) when considering the options provided. Therefore, the closest option to the computed perimeter of a square with a side length of \( \sqrt{212} \) is:

\[
\boxed{8\sqrt{48}}
\]

as it compares favorably in magnitude to \(8\sqrt{53}\).

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