Use the image to answer the question.

The length, width, and height of a cube are all labeled a.

A cube has an edge length, a
, that is a rational number of centimeters. Identify which measurement will require the use of irrational numbers.

(1 point)
Responses

the volume of the cube
the volume of the cube

the diagonal of one of the cube’s faces
the diagonal of one of the cube’s faces

the surface area of the cube
the surface area of the cube

the area of one of the cube’s faces
the area of one of the cube’s faces

1 answer

To determine which measurement will require the use of irrational numbers, let's analyze the options in the context of a cube with edge length \( a \):

  1. The volume of the cube: The volume \( V \) of a cube is calculated using the formula \( V = a^3 \). Since \( a \) is a rational number, \( a^3 \) will also be rational.

  2. The diagonal of one of the cube’s faces: The diagonal \( d \) of a face of the cube can be calculated using the Pythagorean theorem: \( d = \sqrt{a^2 + a^2} = \sqrt{2a^2} = a\sqrt{2} \). Since \( \sqrt{2} \) is an irrational number, \( d \) will be irrational when \( a \) is a non-zero rational number.

  3. The surface area of the cube: The surface area \( SA \) of a cube is given by \( SA = 6a^2 \). Both \( 6 \) and \( a^2 \) are rational, so the surface area is rational.

  4. The area of one of the cube’s faces: The area \( A \) of one face of the cube is \( A = a^2 \). Since \( a \) is rational, \( a^2 \) is also rational.

Based on this analysis, the measurement that requires the use of irrational numbers is:

the diagonal of one of the cube’s faces.