Question

3(3n+5)+1=2(n-20)

Answer 1

Let's solve the equation step by step:

The given equation is:

\[ 3(3n + 5) + 1 = 2(n - 20) \]

First, distribute the numbers outside the parentheses:

\[ 9n + 15 + 1 = 2n - 40 \]

Now combine like terms on the left side:

\[ 9n + 16 = 2n - 40 \]

Next, let's isolate the \( n \) terms by subtracting \( 2n \) from both sides:

\[ 9n - 2n + 16 = -40 \]
\[ 7n + 16 = -40 \]

Now, subtract 16 from both sides:

\[ 7n = -40 - 16 \]
\[ 7n = -56 \]

Finally, divide both sides by 7:

\[ n = -\frac{56}{7} \]
\[ n = -8 \]

So, the solution is:

\[ n = -8 \]