Atlanta list the ages of all of the family members who live in her house what is the mean absolute deviation of their ages age 9 age 13 age 43 age 55 a28 b38 C 76 d19

To find the mean absolute deviation (MAD) of the ages, follow these steps:

1. **List the ages**: 9, 13, 43, 55, 28, 38.

2. **Calculate the mean**:
\[
\text{Mean} = \frac{(9 + 13 + 43 + 55 + 28 + 38)}{6} = \frac{186}{6} = 31
\]

3. **Calculate the absolute deviations from the mean**:
\[
|9 - 31| = 22
\]
\[
|13 - 31| = 18
\]
\[
|43 - 31| = 12
\]
\[
|55 - 31| = 24
\]
\[
|28 - 31| = 3
\]
\[
|38 - 31| = 7
\]

4. **List the absolute deviations**: 22, 18, 12, 24, 3, 7.

5. **Calculate the mean of the absolute deviations**:
\[
\text{MAD} = \frac{(22 + 18 + 12 + 24 + 3 + 7)}{6} = \frac{86}{6} \approx 14.33
\]

So the mean absolute deviation of the ages is approximately **14.33**.

If you're interested in the options provided (A 28, B 38, C 76, D 19), none of these match the calculated mean absolute deviation.

Please verify your options or the question requirements.