Question
Use the image to answer the question.
A descending curve with an arrow on the right end passes through 10 points plotted on a coordinate plane. The x-axis is labeled years since purchase, and the y-axis is labeled value of car.
Given the graph of the exponential equation representing the value of a car since purchase, which option is the correct exponential equation for the graph if the graph goes through the points (0, 30000) and (1, 22500) ?
(1 point)
Responses
y=22,500(34)x
y equals 22,500 left parenthesis Start Fraction 3 over 4 End Fraction right parenthesis superscript x baseline
y=30,000(43)x
y equals 30,000 left parenthesis Start Fraction 4 over 3 End Fraction right parenthesis superscript x baseline
y=0.75(30,000)x
y equals 0.75 left parenthesis 30,000 right parenthesis superscript x baseline
y=30,000(34)x
y equals 30,000 left parenthesis Start Fraction 3 over 4 End Fraction right parenthesis superscript x baseline
A descending curve with an arrow on the right end passes through 10 points plotted on a coordinate plane. The x-axis is labeled years since purchase, and the y-axis is labeled value of car.
Given the graph of the exponential equation representing the value of a car since purchase, which option is the correct exponential equation for the graph if the graph goes through the points (0, 30000) and (1, 22500) ?
(1 point)
Responses
y=22,500(34)x
y equals 22,500 left parenthesis Start Fraction 3 over 4 End Fraction right parenthesis superscript x baseline
y=30,000(43)x
y equals 30,000 left parenthesis Start Fraction 4 over 3 End Fraction right parenthesis superscript x baseline
y=0.75(30,000)x
y equals 0.75 left parenthesis 30,000 right parenthesis superscript x baseline
y=30,000(34)x
y equals 30,000 left parenthesis Start Fraction 3 over 4 End Fraction right parenthesis superscript x baseline
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the correct exponential equation for the value of a car since its purchase, we can use the information provided from the points (0, 30000) and (1, 22500).
1. **Determine the initial value (at x=0)**: At \( x = 0 \), the value of the car is \( y = 30000 \). Therefore, the equation will have the form:
\[
y = 30000 \cdot a^x
\]
2. **Use the second point (1, 22500)**: At \( x = 1 \), the value of the car is \( y = 22500 \). Plugging this into the equation gives us:
\[
22500 = 30000 \cdot a^1
\]
3. **Solve for \( a \)**:
\[
a = \frac{22500}{30000} = \frac{3}{4}
\]
4. **Formulate the exponential equation**: Now substituting \( a \) back into the original equation, we have:
\[
y = 30000 \left(\frac{3}{4}\right)^x
\]
This matches the fourth option given in the responses:
\[
y = 30,000 \left(\frac{3}{4}\right)^x
\]
Thus, the correct exponential equation representing the graph is:
\[
\boxed{y = 30,000 \left(\frac{3}{4}\right)^x}
\]
1. **Determine the initial value (at x=0)**: At \( x = 0 \), the value of the car is \( y = 30000 \). Therefore, the equation will have the form:
\[
y = 30000 \cdot a^x
\]
2. **Use the second point (1, 22500)**: At \( x = 1 \), the value of the car is \( y = 22500 \). Plugging this into the equation gives us:
\[
22500 = 30000 \cdot a^1
\]
3. **Solve for \( a \)**:
\[
a = \frac{22500}{30000} = \frac{3}{4}
\]
4. **Formulate the exponential equation**: Now substituting \( a \) back into the original equation, we have:
\[
y = 30000 \left(\frac{3}{4}\right)^x
\]
This matches the fourth option given in the responses:
\[
y = 30,000 \left(\frac{3}{4}\right)^x
\]
Thus, the correct exponential equation representing the graph is:
\[
\boxed{y = 30,000 \left(\frac{3}{4}\right)^x}
\]
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