To determine which of the given equations has exactly one solution, we can analyze each one:
-
\(3x + 4 = 4x + 3\)
Rearranging gives:
\(3x + 4 - 4x - 3 = 0\)
\(-x + 1 = 0\)
This has one solution: \(x = 1\). -
\(4x + 3 = 4x + 3\)
This equation is always true for any value of \(x\). Thus, it has infinitely many solutions. -
\(3x + 4 = 3x + 4\)
Like the previous one, this equation is always true for any \(x\) and has infinitely many solutions. -
\(3x + 4 = 3x + 3\)
Rearranging gives:
\(3x + 4 - 3x - 3 = 0\)
\(1 = 0\)
This is a contradiction, so it has no solutions.
Based on this analysis, the equation with exactly one solution is:
\(3x + 4 = 4x + 3\).