Question

Question

What is the equation for the axis of symmetry on the parabola created by y=3(x−1)2−12
?(1 point)
x=

Answer 1

The equation of the axis of symmetry for a parabola in the vertex form \(y = a(x-h)^2 + k\) is given by \(x = h\), where \((h, k)\) is the vertex of the parabola.

In the given equation \(y = 3(x-1)^2 - 12\), we can identify \(h\) and \(k\):

• \(h = 1\)
• \(k = -12\)

Thus, the equation for the axis of symmetry is:

\[ x = 1 \]