Question
Could you do an expression subtracting radicals using this equation?
?sqrt(?) - ?sqrt(?) = ? sqrt (?)
?sqrt(?) - ?sqrt(?) = ? sqrt (?)
Answers
Answered by
GPT-4o mini
Certainly! Let's work with the expression in the form \( a\sqrt{b} - c\sqrt{d} = e\sqrt{f} \). Here's an example to illustrate the subtraction of radicals:
\[
3\sqrt{8} - 2\sqrt{2} = e\sqrt{f}
\]
First, we simplify \(3\sqrt{8}\):
\[
\sqrt{8} = \sqrt{4 \cdot 2} = \sqrt{4} \cdot \sqrt{2} = 2\sqrt{2}
\]
Thus,
\[
3\sqrt{8} = 3 \cdot 2\sqrt{2} = 6\sqrt{2}
\]
Now, we can rewrite the expression:
\[
6\sqrt{2} - 2\sqrt{2} = (6 - 2)\sqrt{2} = 4\sqrt{2}
\]
So we have:
\[
3\sqrt{8} - 2\sqrt{2} = 4\sqrt{2}
\]
Thus, assigning the values gives:
- \( a = 3 \)
- \( b = 8 \)
- \( c = 2 \)
- \( d = 2 \)
- \( e = 4 \)
- \( f = 2 \)
So the original equation works out as:
\[
3\sqrt{8} - 2\sqrt{2} = 4\sqrt{2}
\]
Feel free to ask if you'd like to see another example!
\[
3\sqrt{8} - 2\sqrt{2} = e\sqrt{f}
\]
First, we simplify \(3\sqrt{8}\):
\[
\sqrt{8} = \sqrt{4 \cdot 2} = \sqrt{4} \cdot \sqrt{2} = 2\sqrt{2}
\]
Thus,
\[
3\sqrt{8} = 3 \cdot 2\sqrt{2} = 6\sqrt{2}
\]
Now, we can rewrite the expression:
\[
6\sqrt{2} - 2\sqrt{2} = (6 - 2)\sqrt{2} = 4\sqrt{2}
\]
So we have:
\[
3\sqrt{8} - 2\sqrt{2} = 4\sqrt{2}
\]
Thus, assigning the values gives:
- \( a = 3 \)
- \( b = 8 \)
- \( c = 2 \)
- \( d = 2 \)
- \( e = 4 \)
- \( f = 2 \)
So the original equation works out as:
\[
3\sqrt{8} - 2\sqrt{2} = 4\sqrt{2}
\]
Feel free to ask if you'd like to see another example!