Asked by k
Solve for x to determine if the equation has one, none, or infinite solutions 9 (x+1)=3(5x+1)−12
The equation has one solution: x=3.
The equation has one solution: x=0.
The equation has one solution: x=3.
The equation has one solution: x=0.
Answers
Answered by
GPT-4o mini
Let's solve the equation step by step to determine the solution for \( x \) and to see if the equation has one, none, or infinite solutions.
The given equation is:
\[
9 (x + 1) = 3(5x + 1) - 12
\]
First, we'll expand both sides of the equation.
**Left side:**
\[
9(x + 1) = 9x + 9
\]
**Right side:**
\[
3(5x + 1) - 12 = 15x + 3 - 12 = 15x - 9
\]
Now the equation can be rewritten as:
\[
9x + 9 = 15x - 9
\]
Next, we'll move all terms involving \( x \) to one side and constant terms to the other side. We'll subtract \( 9x \) from both sides:
\[
9 = 15x - 9x - 9
\]
This simplifies to:
\[
9 = 6x - 9
\]
Next, add \( 9 \) to both sides of the equation:
\[
9 + 9 = 6x
\]
\[
18 = 6x
\]
Now, divide both sides by \( 6 \):
\[
x = \frac{18}{6} = 3
\]
So, we have found one solution:
\[
x = 3
\]
Now, let's summarize:
The equation has **one solution**, which is \( x = 3 \).
Thus, the answer is:
- The equation has one solution: \( x = 3 \).
The given equation is:
\[
9 (x + 1) = 3(5x + 1) - 12
\]
First, we'll expand both sides of the equation.
**Left side:**
\[
9(x + 1) = 9x + 9
\]
**Right side:**
\[
3(5x + 1) - 12 = 15x + 3 - 12 = 15x - 9
\]
Now the equation can be rewritten as:
\[
9x + 9 = 15x - 9
\]
Next, we'll move all terms involving \( x \) to one side and constant terms to the other side. We'll subtract \( 9x \) from both sides:
\[
9 = 15x - 9x - 9
\]
This simplifies to:
\[
9 = 6x - 9
\]
Next, add \( 9 \) to both sides of the equation:
\[
9 + 9 = 6x
\]
\[
18 = 6x
\]
Now, divide both sides by \( 6 \):
\[
x = \frac{18}{6} = 3
\]
So, we have found one solution:
\[
x = 3
\]
Now, let's summarize:
The equation has **one solution**, which is \( x = 3 \).
Thus, the answer is:
- The equation has one solution: \( x = 3 \).
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