Asked by Bella
Consider the unbalanced equation: Na+Cl2 = NaCl. What mass of NaCl can be produced from 25.0 grams of Chlorine?
Answers
Answered by
DrBob222
1. Balance the equation.
2. Convert 25.0 g Cl2 to moles. moles = gram/molar mass.
3. Using the coefficients in the balanced equation, convert moles Cl2 to moles NaCl.
4. Now convert moles NaCl to grams NaCl. Grams NaCl = moles NaCl x molar mass NaCl.
Post your work if you get stuck.
2. Convert 25.0 g Cl2 to moles. moles = gram/molar mass.
3. Using the coefficients in the balanced equation, convert moles Cl2 to moles NaCl.
4. Now convert moles NaCl to grams NaCl. Grams NaCl = moles NaCl x molar mass NaCl.
Post your work if you get stuck.
Answered by
Nadia Samim
FIRST, blance the equation.
2Na + CL2 -> 2NaCl
SECOND, get the g ( atomic mass. ) for NaCl and Cl.
NaCL--V
2Na- 23.00 x 2 = 66.00g
2CL- 35.45 x 2 = 70.9g
Add the two together.
NaCal = 137g
Cl--V
2Cl- 35.45 x 2 = 70.9g
Cl = 70.9G
LAST,
Set up your equation, starting with the 25g of Cl you have.
25gCl2 x 1 molCl2/70.9gCl x 2 mol NaCl/1 mol Cl2 = ( Your answer! )
Hope I helped. (:
2Na + CL2 -> 2NaCl
SECOND, get the g ( atomic mass. ) for NaCl and Cl.
NaCL--V
2Na- 23.00 x 2 = 66.00g
2CL- 35.45 x 2 = 70.9g
Add the two together.
NaCal = 137g
Cl--V
2Cl- 35.45 x 2 = 70.9g
Cl = 70.9G
LAST,
Set up your equation, starting with the 25g of Cl you have.
25gCl2 x 1 molCl2/70.9gCl x 2 mol NaCl/1 mol Cl2 = ( Your answer! )
Hope I helped. (:
Answered by
DrBob222
SECOND, get the g ( atomic mass. ) for NaCl and Cl.
NaCL--V
2Na- 23.00 x 2 = 66.00g
2CL- 35.45 x 2 = 70.9g
Add the two together.
NaCal = 137g
<b>2 x 23.00 = 46.00, not 66.00
total 2NaCl should be 117, not 137.</b>
NaCL--V
2Na- 23.00 x 2 = 66.00g
2CL- 35.45 x 2 = 70.9g
Add the two together.
NaCal = 137g
<b>2 x 23.00 = 46.00, not 66.00
total 2NaCl should be 117, not 137.</b>
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.