Question
John invested K15000 at an interest rate of 6% p.a. for 30 months.
a. Calculate his simple interest
b. Calculate his installments compounded every two months.
a. Calculate his simple interest
b. Calculate his installments compounded every two months.
Answers
GPT-4o mini
To solve the problem, we need to follow these steps:
### a. Calculate Simple Interest
Simple interest can be calculated using the formula:
\[
\text{Simple Interest} = P \times r \times t
\]
Where:
- \( P \) = Principal amount (initial investment)
- \( r \) = Annual interest rate (in decimal)
- \( t \) = Time (in years)
Given:
- \( P = K15000 \)
- \( r = 6\% = 0.06 \)
- \( t = 30 \text{ months} = \frac{30}{12} \text{ years} = 2.5 \text{ years} \)
Now, plug in the values:
\[
\text{Simple Interest} = 15000 \times 0.06 \times 2.5
\]
Calculating this step-by-step:
1. Calculate \( 0.06 \times 2.5 = 0.15 \)
2. Calculate \( 15000 \times 0.15 = 2250 \)
Thus, the simple interest is:
\[
\text{Simple Interest} = K2250
\]
### b. Calculate Compound Interest Compounded Every Two Months
To calculate the compound interest, we can use the formula:
\[
A = P \left(1 + \frac{r}{n}\right)^{nt}
\]
Where:
- \( A \) = Amount of money accumulated after n years, including interest.
- \( P \) = Principal amount (initial investment)
- \( r \) = Annual interest rate (in decimal)
- \( n \) = Number of times that interest is compounded per year
- \( t \) = Time (in years)
Given:
- \( P = K15000 \)
- \( r = 6\% = 0.06 \)
- Compounding every two months means \( n = 6 \) (as there are 6 two-month periods in a year)
- \( t = 30 \text{ months} = \frac{30}{12} \text{ years} = 2.5 \text{ years} \)
Now, plug in the values:
\[
A = 15000 \left(1 + \frac{0.06}{6}\right)^{6 \times 2.5}
\]
Calculate \( \frac{0.06}{6} = 0.01 \) and \( 6 \times 2.5 = 15 \).
Thus, the formula becomes:
\[
A = 15000 \left(1 + 0.01\right)^{15}
\]
Calculate:
\[
A = 15000 \left(1.01\right)^{15}
\]
Now calculate \( (1.01)^{15} \):
\[
(1.01)^{15} \approx 1.16079 \quad (\text{you may use a calculator for precision})
\]
Now, plug this back into the amount formula:
\[
A \approx 15000 \times 1.16079 \approx 17411.85
\]
Finally, the compound interest earned is:
\[
\text{Compound Interest} = A - P = 17411.85 - 15000 = K2411.85
\]
### Summary of Results
a. The simple interest earned is **K2250**.
b. The amount after compounding every two months is approximately **K17411.85**, and the compound interest earned is approximately **K2411.85**.
### a. Calculate Simple Interest
Simple interest can be calculated using the formula:
\[
\text{Simple Interest} = P \times r \times t
\]
Where:
- \( P \) = Principal amount (initial investment)
- \( r \) = Annual interest rate (in decimal)
- \( t \) = Time (in years)
Given:
- \( P = K15000 \)
- \( r = 6\% = 0.06 \)
- \( t = 30 \text{ months} = \frac{30}{12} \text{ years} = 2.5 \text{ years} \)
Now, plug in the values:
\[
\text{Simple Interest} = 15000 \times 0.06 \times 2.5
\]
Calculating this step-by-step:
1. Calculate \( 0.06 \times 2.5 = 0.15 \)
2. Calculate \( 15000 \times 0.15 = 2250 \)
Thus, the simple interest is:
\[
\text{Simple Interest} = K2250
\]
### b. Calculate Compound Interest Compounded Every Two Months
To calculate the compound interest, we can use the formula:
\[
A = P \left(1 + \frac{r}{n}\right)^{nt}
\]
Where:
- \( A \) = Amount of money accumulated after n years, including interest.
- \( P \) = Principal amount (initial investment)
- \( r \) = Annual interest rate (in decimal)
- \( n \) = Number of times that interest is compounded per year
- \( t \) = Time (in years)
Given:
- \( P = K15000 \)
- \( r = 6\% = 0.06 \)
- Compounding every two months means \( n = 6 \) (as there are 6 two-month periods in a year)
- \( t = 30 \text{ months} = \frac{30}{12} \text{ years} = 2.5 \text{ years} \)
Now, plug in the values:
\[
A = 15000 \left(1 + \frac{0.06}{6}\right)^{6 \times 2.5}
\]
Calculate \( \frac{0.06}{6} = 0.01 \) and \( 6 \times 2.5 = 15 \).
Thus, the formula becomes:
\[
A = 15000 \left(1 + 0.01\right)^{15}
\]
Calculate:
\[
A = 15000 \left(1.01\right)^{15}
\]
Now calculate \( (1.01)^{15} \):
\[
(1.01)^{15} \approx 1.16079 \quad (\text{you may use a calculator for precision})
\]
Now, plug this back into the amount formula:
\[
A \approx 15000 \times 1.16079 \approx 17411.85
\]
Finally, the compound interest earned is:
\[
\text{Compound Interest} = A - P = 17411.85 - 15000 = K2411.85
\]
### Summary of Results
a. The simple interest earned is **K2250**.
b. The amount after compounding every two months is approximately **K17411.85**, and the compound interest earned is approximately **K2411.85**.