Lines AC and BD intersect at point O.

Lines AC and BD intersect at point O.

If m∠AOD = (5x − 4)° and m∠BOC = (4x + 5)°, what is m∠BOC?


10°
41°
82°

1 answer

Since lines AC and BD intersect at point O, the angles ∠AOD and ∠BOC are vertical angles. Vertical angles are equal, so we can set the expressions for the angles equal to each other:

\[ m∠AOD = m∠BOC \]

Given that:

\[ m∠AOD = (5x - 4)° \] \[ m∠BOC = (4x + 5)° \]

We can set up the equation:

\[ 5x - 4 = 4x + 5 \]

Now, let's solve for \(x\):

  1. Subtract \(4x\) from both sides:

\[ 5x - 4x - 4 = 5 \]

This simplifies to:

\[ x - 4 = 5 \]

  1. Add 4 to both sides:

\[ x = 9 \]

Now that we have the value of \(x\), we can substitute it back to find \(m∠BOC\):

\[ m∠BOC = 4x + 5 \]

Substituting \(x = 9\):

\[ m∠BOC = 4(9) + 5 = 36 + 5 = 41° \]

Thus, the measure of angle \(BOC\) is:

\[ \boxed{41°} \]

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