To determine which of the given differences would result in a rational number, we need to analyze each expression individually.
-
\(5 - \sqrt{2}\): This involves rational number 5 and the irrational number \( \sqrt{2} \). The difference will be irrational because the subtraction of a rational and an irrational number is always irrational.
-
\( \sqrt{36} - \frac{2}{3} \): The first term, \( \sqrt{36} \), is 6, which is a rational number. Subtracting another rational number \( \frac{2}{3} \) from it results in \( 6 - \frac{2}{3} = \frac{18}{3} - \frac{2}{3} = \frac{16}{3} \), which is a rational number.
-
\( \pi - 1 \): Here, \( \pi \) is an irrational number, and 1 is a rational number. The difference \( \pi - 1 \) is still irrational.
-
\( 6.2\overline{6} - \sqrt{3} \): The number \( 6.2\overline{6} \) is a rational number (it is equivalent to \( \frac{188}{30} \)). \( \sqrt{3} \) is an irrational number, so the difference would also be irrational.
Based on this analysis, the only expression that results in a rational number is:
\( \sqrt{36} - \frac{2}{3} \).