7(3a+4)=11(a-1)+19

1 answer

Let's solve the equation step by step:

Given: \[ 7(3a + 4) = 11(a - 1) + 19 \]

  1. Distribute on both sides: \[ 21a + 28 = 11a - 11 + 19 \]

    Simplifying the right side: \[ 11a - 11 + 19 = 11a + 8 \] So we rewrite the equation as: \[ 21a + 28 = 11a + 8 \]

  2. Next, we'll move all terms involving \(a\) to one side and constant terms to the other side. Subtract \(11a\) from both sides: \[ 21a - 11a + 28 = 8 \] Simplifying gives: \[ 10a + 28 = 8 \]

  3. Now, subtract 28 from both sides: \[ 10a = 8 - 28 \] Simplifying gives: \[ 10a = -20 \]

  4. Finally, divide both sides by 10: \[ a = \frac{-20}{10} = -2 \]

Thus, the solution to the equation is: \[ \boxed{-2} \]