Question

10+[3 times 4^2] divided by 6 over 3-2 times -1

Answer 1

Let's break down the expression step by step.

The expression is:

\[ 10 + \frac{3 \times 4^2}{6} \div (3 - 2 \times -1) \]

1. First, calculate \( 4^2 \):
\[ 4^2 = 16 \]

2. Now, substitute that back into the expression:
\[ 10 + \frac{3 \times 16}{6} \div (3 - 2 \times -1) \]

3. Next, calculate \( 3 \times 16 \):
\[ 3 \times 16 = 48 \]

4. So now, we have:
\[ 10 + \frac{48}{6} \div (3 - 2 \times -1) \]

5. Calculate \( \frac{48}{6} \):
\[ \frac{48}{6} = 8 \]

6. Now, substitute that into the equation:
\[ 10 + 8 \div (3 - 2 \times -1) \]

7. Next, calculate \( 2 \times -1 \):
\[ 2 \times -1 = -2 \]

8. Now, substitute that back in to calculate \( 3 - (-2) \):
\[ 3 - (-2) = 3 + 2 = 5 \]

9. Now our expression looks like this:
\[ 10 + 8 \div 5 \]

10. Next, calculate \( 8 \div 5 \):
\[ 8 \div 5 = 1.6 \]

11. Finally, add that to 10:
\[ 10 + 1.6 = 11.6 \]

So, the answer to the expression is:

\[
\boxed{11.6}
\]