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Original Question
Which equation is equivalent to w=x+y−z? z=x+y+w z=w−x−y z=(x+y)/w z=x+y−wAsked by Just-A-V3nter
                Which equation is equivalent to  w=x+y−z ?
z=w−x−y
z=x+y−w
z=(x+y)w
z=x+y+w
            
        z=w−x−y
z=x+y−w
z=(x+y)w
z=x+y+w
Answers
                                                    There are no human answers yet.
                                            
                
                    Answered by
            GPT-4o mini
            
    To determine which equation is equivalent to \( w = x + y - z \), we can rearrange this equation to solve for \( z \).
Starting with the original equation:
\[
w = x + y - z
\]
We can add \( z \) to both sides:
\[
w + z = x + y
\]
Now, subtract \( w \) from both sides to isolate \( z \):
\[
z = x + y - w
\]
This matches one of the provided options. Rearranging it, we can also express it as:
\[
z = x + y - w
\]
To see which option this corresponds to, let's look at the given options:
1. \( z = w - x - y \) (not equivalent)
2. \( z = x + y - w \) (this matches)
3. \( z = (x + y)w \) (not equivalent)
4. \( z = x + y + w \) (not equivalent)
Thus, the equation that is equivalent to \( w = x + y - z \) is:
\[
\boxed{z = x + y - w}
\]
    
Starting with the original equation:
\[
w = x + y - z
\]
We can add \( z \) to both sides:
\[
w + z = x + y
\]
Now, subtract \( w \) from both sides to isolate \( z \):
\[
z = x + y - w
\]
This matches one of the provided options. Rearranging it, we can also express it as:
\[
z = x + y - w
\]
To see which option this corresponds to, let's look at the given options:
1. \( z = w - x - y \) (not equivalent)
2. \( z = x + y - w \) (this matches)
3. \( z = (x + y)w \) (not equivalent)
4. \( z = x + y + w \) (not equivalent)
Thus, the equation that is equivalent to \( w = x + y - z \) is:
\[
\boxed{z = x + y - w}
\]
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