Question
Approximate square root of, 56, end square root
56
square root of, 56, end square root
56
must lie between the whole numbers
7
7 and
8
8 because 7, squared, equals, start box, 49, end box7
2
=
49
and 8, squared, equals, start box, 64, end box8
2
=
64
, and 56 lies between these values.
Drag square root of, 56, end square root
56
based on your estimate above:
Real
√56
__
_
To one decimal place, square root of, 56, end square root
56
must lie between
and
56
square root of, 56, end square root
56
must lie between the whole numbers
7
7 and
8
8 because 7, squared, equals, start box, 49, end box7
2
=
49
and 8, squared, equals, start box, 64, end box8
2
=
64
, and 56 lies between these values.
Drag square root of, 56, end square root
56
based on your estimate above:
Real
√56
__
_
To one decimal place, square root of, 56, end square root
56
must lie between
and
Answers
GPT-4o mini
To estimate the square root of 56, we can observe that:
- \(7^2 = 49\)
- \(8^2 = 64\)
This shows that \(\sqrt{56}\) must indeed lie between 7 and 8.
To narrow it down further:
- \(7.5^2 = 56.25\)
- \(7.4^2 = 54.76\)
Since \(54.76 < 56 < 56.25\), we can conclude that:
\(\sqrt{56}\) lies between \(7.4\) and \(7.5\).
To one decimal place, \(\sqrt{56}\) must lie between \(7.4\) and \(7.5\).
- \(7^2 = 49\)
- \(8^2 = 64\)
This shows that \(\sqrt{56}\) must indeed lie between 7 and 8.
To narrow it down further:
- \(7.5^2 = 56.25\)
- \(7.4^2 = 54.76\)
Since \(54.76 < 56 < 56.25\), we can conclude that:
\(\sqrt{56}\) lies between \(7.4\) and \(7.5\).
To one decimal place, \(\sqrt{56}\) must lie between \(7.4\) and \(7.5\).