Question

A buoy bobs up and down in the ocean. The waves have a wavelength of 2.5 meters, and they pass the buoy at a speed of 4.0 meters/second. What is the frequency of the waves?

Note: Frequency = wave speed divided by wavelength

frequency (Hz) = speed (m/s) / wavelength (m)

(1 point)
Responses

1.6 Hertz
1.6 Hertz

10 Hertz
10 Hertz

7.5 Hertz
7.5 Hertz

4 Hertz

Answer 1

To calculate the frequency of the waves, we can use the formula:

\[ \text{frequency} \, (f) = \frac{\text{speed} \, (v)}{\text{wavelength} \, (\lambda)} \]

Given:
- Wave speed \( v = 4.0 \, \text{m/s} \)
- Wavelength \( \lambda = 2.5 \, \text{m} \)

Now, we can plug in the values:

\[ f = \frac{4.0 \, \text{m/s}}{2.5 \, \text{m}} \]

Calculating this gives:

\[ f = 1.6 \, \text{Hz} \]

Therefore, the correct response is:

**1.6 Hertz**

Answer 2

sure?

Answer 3

Yes, I am sure. Let's walk through the calculation again for clarity:

1. **Formula for frequency**:
\[
f = \frac{v}{\lambda}
\]
where \( f \) is the frequency in Hertz, \( v \) is the wave speed in meters per second, and \( \lambda \) is the wavelength in meters.

2. **Substituting the values**:
- Wave speed \( v = 4.0 \, \text{m/s} \)
- Wavelength \( \lambda = 2.5 \, \text{m} \)

So we substitute:
\[
f = \frac{4.0 \, \text{m/s}}{2.5 \, \text{m}}
\]

3. **Calculating the frequency**:
\[
f = \frac{4.0}{2.5} = 1.6 \, \text{Hz}
\]

Therefore, the frequency of the waves is **1.6 Hertz**. If you have any further questions or would like any additional information, feel free to ask!