A buoy bobs up and down in the ocean. The waves have a wavelength of 2.5 meters, and they pass the buoy at a speed of 4.0 meters/second. What is the frequency of the waves?

Question

Note: Frequency = wave speed divided by wavelength

frequency (Hz) = speed (m/s) / wavelength (m)

(1 point)
Responses

1.6 Hertz
1.6 Hertz

10 Hertz
10 Hertz

7.5 Hertz
7.5 Hertz

4 Hertz

Answer 1

To calculate the frequency of the waves, we can use the formula:

\[ \text{frequency} , (f) = \frac{\text{speed} , (v)}{\text{wavelength} , (\lambda)} \]

Given:

• Wave speed \( v = 4.0 , \text{m/s} \)
• Wavelength \( \lambda = 2.5 , \text{m} \)

Now, we can plug in the values:

\[ f = \frac{4.0 , \text{m/s}}{2.5 , \text{m}} \]

Calculating this gives:

\[ f = 1.6 , \text{Hz} \]

Therefore, the correct response is:

1.6 Hertz

Answer 2

sure?

Answer 3

Yes, I am sure. Let's walk through the calculation again for clarity:

1. Formula for frequency: \[ f = \frac{v}{\lambda} \] where \( f \) is the frequency in Hertz, \( v \) is the wave speed in meters per second, and \( \lambda \) is the wavelength in meters.

2. Substituting the values:

   • Wave speed \( v = 4.0 , \text{m/s} \)
   • Wavelength \( \lambda = 2.5 , \text{m} \)

   So we substitute: \[ f = \frac{4.0 , \text{m/s}}{2.5 , \text{m}} \]

3. Calculating the frequency: \[ f = \frac{4.0}{2.5} = 1.6 , \text{Hz} \]

Therefore, the frequency of the waves is 1.6 Hertz. If you have any further questions or would like any additional information, feel free to ask!