determine if these are liner relationships or not

(-2,-17)(-1,-11)(0,-5)(1,1)(2,7)(3,13)

1 answer

To determine if the given points \((-2,-17)\), \((-1,-11)\), \((0,-5)\), \((1,1)\), \((2,7)\), and \((3,13)\) represent a linear relationship, we can check if the slope between each pair of consecutive points is constant.

The formula for the slope \(m\) between two points \((x_1,y_1)\) and \((x_2,y_2)\) is given by:

\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]

Now, let's calculate the slope between each pair of consecutive points:

  1. Between points \((-2, -17)\) and \((-1, -11)\): \[ m_1 = \frac{-11 - (-17)}{-1 - (-2)} = \frac{-11 + 17}{-1 + 2} = \frac{6}{1} = 6 \]

  2. Between points \((-1, -11)\) and \((0, -5)\): \[ m_2 = \frac{-5 - (-11)}{0 - (-1)} = \frac{-5 + 11}{0 + 1} = \frac{6}{1} = 6 \]

  3. Between points \((0, -5)\) and \((1, 1)\): \[ m_3 = \frac{1 - (-5)}{1 - 0} = \frac{1 + 5}{1} = \frac{6}{1} = 6 \]

  4. Between points \((1, 1)\) and \((2, 7)\): \[ m_4 = \frac{7 - 1}{2 - 1} = \frac{6}{1} = 6 \]

  5. Between points \((2, 7)\) and \((3, 13)\): \[ m_5 = \frac{13 - 7}{3 - 2} = \frac{6}{1} = 6 \]

Since the slope is constant at \(6\) for all consecutive pairs of points, we conclude that the relationship represented by the given points is indeed linear.

Similar Questions
  1. determine if these are liner relationships or not(-2,-7)(-1,-3)(0,2)(1,8)(2,15)(3,23)
    1. answers icon 1 answer
  2. determine if these are liner relationships or not(-2,-4)(-1,1)(0,0)(1,1)(2,4)(3,9)
    1. answers icon 1 answer
  3. determine if these are liner relationships or not(-2,-12)(-1,10)(0,8)(1,6)(2,4)(3,2)
    1. answers icon 1 answer
  4. determine if these are liner relationships or not(-2,2)(-1,0)(0,0)(1,2)(2,6)(3,12)
    1. answers icon 1 answer
more similar questions