Solve the following work problem the air temperature at 9:00 a.m. is-5.8° C the air temperature at noon is -1.6° C what is the change in the temperature during these three hours right and solve an equation to show your answer then explain what your answer means

Answer 1

To find the change in temperature from 9:00 a.m. to noon, we can set up an equation using the initial and final temperatures.

1. Define the Variables:

   • Let \( T_1 \) be the temperature at 9:00 a.m.: \( T_1 = -5.8 , ^\circ C \)
   • Let \( T_2 \) be the temperature at noon: \( T_2 = -1.6 , ^\circ C \)
   • Let \( \Delta T \) be the change in temperature.

2. Set up the equation: \[ \Delta T = T_2 - T_1 \] Substituting the given temperatures: \[ \Delta T = -1.6 - (-5.8) \]

3. Calculate: \[ \Delta T = -1.6 + 5.8 \] \[ \Delta T = 4.2 , ^\circ C \]

The change in temperature during these three hours is \( 4.2 , ^\circ C \).

Explanation of the Answer

This result means that from 9:00 a.m. to noon, the temperature increased by \( 4.2 , ^\circ C \). In simpler terms, the weather became warmer over this time period. Starting at a rather cold temperature of \( -5.8 , ^\circ C \) in the morning, it rose to a still chilly but much less severe \( -1.6 , ^\circ C \) by noon. This change could be due to various environmental factors such as the sun rising higher in the sky and warming the air.