Solve for x: −12x + 20 = −10x + 32

Question

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Answer 1

To solve the equation \(-12x + 20 = -10x + 32\), follow these steps:

1. Rearrange the equation to isolate \(x\). Start by adding \(12x\) to both sides:

   \[ 20 = 2x + 32 \]

2. Next, subtract \(32\) from both sides:

   \[ 20 - 32 = 2x \]

   This simplifies to:

   \[ -12 = 2x \]

3. Now, divide both sides by \(2\) to solve for \(x\):

   \[ x = -6 \]

Thus, the solution is:

\[ \boxed{-6} \]

Answer 2

Solve
ax + 3 = 33
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Answer 3

To solve the equation \( ax + 3 = 33 \) for \( x \), follow these steps:

1. Subtract 3 from both sides to isolate the term with \( x \):

   \[ ax = 33 - 3 \]

   This simplifies to:

   \[ ax = 30 \]

2. Divide both sides by \( a \) (assuming \( a \neq 0 \)) to solve for \( x \):

   \[ x = \frac{30}{a} \]

Thus, the solution is:

\[ x = \frac{30}{a} \]

Make sure \( a \) is not equal to zero, as division by zero is undefined.