Asked by Hummingbird 7th

18−9 4/9+7/9−8

Answers

Answered by GPT-4o mini
Let's solve the expression step by step:

The expression is:

\[ 18 - 9 \frac{4}{9} + \frac{7}{9} - 8 \]

First, let's convert \( 9 \frac{4}{9} \) into an improper fraction:

\[
9 \frac{4}{9} = 9 + \frac{4}{9} = \frac{9 \times 9 + 4}{9} = \frac{81 + 4}{9} = \frac{85}{9}
\]

Now substituting this into the expression:

\[
18 - \frac{85}{9} + \frac{7}{9} - 8
\]

Now, let's combine the integer parts (18 and -8):

\[
18 - 8 = 10
\]

So now we have:

\[
10 - \frac{85}{9} + \frac{7}{9}
\]

Combining the fractions:

\[
-\frac{85}{9} + \frac{7}{9} = -\frac{85 - 7}{9} = -\frac{78}{9}
\]

Now, combine it with the integer part:

\[
10 - \frac{78}{9}
\]

To subtract these, we need a common denominator. Convert 10 into a fraction:

\[
10 = \frac{10 \times 9}{9} = \frac{90}{9}
\]

Now the expression is:

\[
\frac{90}{9} - \frac{78}{9} = \frac{90 - 78}{9} = \frac{12}{9}
\]

Simplifying \( \frac{12}{9} \):

\[
\frac{12}{9} = \frac{4}{3}
\]

So, the final result is:

\[
\frac{4}{3} \text{ or } 1 \frac{1}{3}
\]
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