To simplify the expression \( \sqrt{28} + 3\sqrt{63} \), we'll follow the steps provided and put them in the correct order:
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Start with \( \sqrt{28} + 3\sqrt{63} \).
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Rewrite each square root in terms of their prime factors:
- \( \sqrt{28} = \sqrt{4 \cdot 7} = \sqrt{4} \cdot \sqrt{7} = 2\sqrt{7} \)
- \( \sqrt{63} = \sqrt{9 \cdot 7} = \sqrt{9} \cdot \sqrt{7} = 3\sqrt{7} \)
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Now the expression is: \[ 2\sqrt{7} + 3\cdot3\sqrt{7} = 2\sqrt{7} + 9\sqrt{7} \]
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Combine like terms: \[ 2\sqrt{7} + 9\sqrt{7} = 11\sqrt{7} \]
Now we can arrange the given steps in the correct order based on how we simplified the expression:
- Step 3: \( \sqrt{2} \cdot 2 \cdot 7 + 3\sqrt{3} \cdot 3 \cdot 7 \)
- Step 5: \( \sqrt{4} \cdot 7 + 3\sqrt{9} \cdot 7 \)
- Step 4: \( 2\sqrt{7} + 3 \cdot 3\sqrt{7} \)
- Step 2: \( 2\sqrt{7} + 9\sqrt{7} \)
- Step 1: \( 11\sqrt{7} \)
So, the correct order of the steps is: 3, 5, 4, 2, 1.